Je posterai les vidΓ©os sur les suites sur le compte @Jade #maths #bac | math
3:21
TikToknba.ja2
Je posterai les vidéos sur les suites sur le compte @Jade #maths #bac | math
Jade(@nba.ja2). son original - Jade. Je posterai les vidéos sur les suites sur le compte @Jade #maths #bac
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Replying to @ahar i honestly contemplated posting this because it was such a distressing time during my graduating year. but after seeing ppl’s comments that they also experienced something similar yet chose to stay silent. trust me, i was so so scared too yet i still did it. so here’s me crying my balls out after that moment πŸ’€ its been 2 months since i graduated grade 12 so i guess im more open about the troubles i went thru getting valedictorian. i hope this video somehow shows the reality of
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Replying to @ahar i honestly contemplated posting this because it was such a distressing time during my graduating year. but after seeing ppl’s comments that they also experienced something similar yet chose to stay silent. trust me, i was so so scared too yet i still did it. so here’s me crying my balls out after that moment πŸ’€ its been 2 months since i graduated grade 12 so i guess im more open about the troubles i went thru getting valedictorian. i hope this video somehow shows the reality of
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Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
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Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
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Replying to @ahar i honestly contemplated posting this because it was such a distressing time during my graduating year. but after seeing ppl’s comments that they also experienced something similar yet chose to stay silent. trust me, i was so so scared too yet i still did it. so here’s me crying my balls out after that moment πŸ’€ its been 2 months since i graduated grade 12 so i guess im more open about the troubles i went thru getting valedictorian. i hope this video somehow shows the reality of
0:57
Replying to @ahar i honestly contemplated posting this because it was such a distressing time during my graduating year. but after seeing ppl’s comments that they also experienced something similar yet chose to stay silent. trust me, i was so so scared too yet i still did it. so here’s me crying my balls out after that moment πŸ’€ its been 2 months since i graduated grade 12 so i guess im more open about the troubles i went thru getting valedictorian. i hope this video somehow shows the reality of
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Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
2:16
Q) Simplify : .cos^(βˆ’1) ((sinπ‘₯+cosπ‘₯)/√2),πœ‹/4=π‘₯=5πœ‹/4 #shivangmathsacademy #maths #cbsemaths
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YouTubeShivang Maths Academy
Q) Evaluate[tan^(βˆ’1) tan(3πœ‹/4)]..#class12maths #shivangmathsacademy #cbsemaths #class12th
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Q) Evaluate tan[cos^(βˆ’1) (tan 3πœ‹/4)].#class12maths #shivangmathsacademy #cbsemaths #class12th
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Q) Evaluate sin[cos^(βˆ’1) cos(7πœ‹/6)] #shivangmathsacademy #cbsemaths #class12maths #maths
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Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
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Q) Simplify : tan^(βˆ’1) ((cos2π‘₯βˆ’sin2π‘₯)/(cos2π‘₯+sin2π‘₯)),0=π‘₯=πœ‹/4..#class12maths #shivangmathsaca
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Q) The graph of a trigonometric function is as shown. Which of the following will represent graph of
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Q) The following graph represents (A) 𝑦=cos^(βˆ’1) π‘₯ (B) 𝑦=sec^(βˆ’1) π‘₯ (C) 𝑦=sin^(βˆ’1) π‘₯ (D)
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Q) Draw the graph of π‘π‘œπ‘ ^(βˆ’1) π‘₯, where π‘₯∈[βˆ’1, 0]. Also, write its range.
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Find the domain of the function 𝑓(π‘₯)= 𝑠𝑖𝑛^(βˆ’1) (π‘₯^2βˆ’4). Also, find its range.#inversetrigonom
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Q) Find the domain of cos^(βˆ’1) (3π‘₯βˆ’2) #shivangmathsacademy #maths #cbsemaths #mathsschool
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If 𝑦=𝑠𝑖𝑛^(βˆ’1) π‘₯,βˆ’1≀π‘₯≀0,then the range of 𝑦 is(A) ((βˆ’πœ‹)/2,0)(B) [(βˆ’πœ‹)/2,0](C) [(βˆ’πœ‹)/2,0
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Q) Find the domain of 𝑓(π‘₯)=π‘π‘œπ‘ ^(βˆ’1) (1βˆ’π‘₯^2 ). Also, find its range..#class12mathsinhindi
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Q) Domain of 𝑠𝑖𝑛^(βˆ’1) (2π‘₯^2βˆ’3) is (A) (βˆ’1,0)βˆͺ(1,√2)(B) (βˆ’βˆš2,βˆ’1)βˆͺ(0,1)(C) [βˆ’βˆš2,βˆ’1]βˆͺ[1,√2](D) (βˆ’
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Q) Find the domain of 𝑔(π‘₯)=cos^(βˆ’1) (π‘₯^2βˆ’1). Hence, find the value of π‘₯ for which 𝑔(π‘₯)=πœ‹/3.
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Q) For the inverse trigonometric functions, which of the following Principal Value Branch
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YouTubeShivang Maths Academy
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